Optics Question 956

Question: An isosceles trapezium of reflecting material of refractive index $ \sqrt{2} $ and dimension of sides being 5 cm, 5 cm, 10 cm and 5 cm. The angle of minimum deviation by this when light is incident from air and emerges in air is:

Options:

A) $ 22\frac{1}{2}{}^\circ $

B) $ 45{}^\circ $

C) $ 30{}^\circ $

D) $ 60{}^\circ $

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Answer:

Correct Answer: D

Solution:

[d] If we complete the trapezium as shown it becomes an equilateral triangle

$ \Rightarrow $ $ A=60^{o} $ $ \frac{\sin [ \frac{A+{\delta _{\min }}}{2} ]}{sin\frac{A}{2}}=\mu $ $ \frac{\sin [ \frac{60+{\delta _{\min }}}{2} ]}{\sin \frac{60}{2}}=\sqrt{2} $ $ {\delta _{\min }}=30{}^\circ $



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