SATHEE: Optics Question 954

Optics Question 954

Question: A plane mirror is made of glass slab $(μ_{g} = 1.5) 2.5 c m$ thick and silvered on the back. A point object is placed 5 cm in front of the unsilvered face of the mirror. What will be the position of final image:

Options:

A) 12 cm from front face

B) 14.6 cm from front face

C) 5.67 cm from front face

D) 8.33 cm from front face

Show Answer

Answer:

Correct Answer: D

Solution:

[d] Let, $I_{1}, I_{2}$ and $I_{3}$ be the images formed by:

(i) refraction from ABC

(ii) reflection from DEF and

(iii) again refraction from ABC

Then $B I_{1} = (5) (μ_{g}) = (5) (1.5) = 7.5 c m$

Now, $E I_{1} = (7.5 + 2.5) = 10 c m$

Hence, $E I_{2} = 10 c m$ behind the mirror

$B I_{2} = (10 + 2.5) = 12.5 c m$

$∴$ $B I_{3} = \frac{12.5}{μ_{g}} = \frac{12.5}{1.5} = 8.33 c m$

The ray diagram is as follow:

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Optics Question 954

Question: A plane mirror is made of glass slab (μg=1.5)2.5cm thick and silvered on the back. A point object is placed 5 cm in front of the unsilvered face of the mirror. What will be the position of final image:

Options:

Answer:

Solution:

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Question: A plane mirror is made of glass slab $(μ_{g} = 1.5) 2.5 c m$ thick and silvered on the back. A point object is placed 5 cm in front of the unsilvered face of the mirror. What will be the position of final image: