Optics Question 935

Question: An object 2.5 cm high is placed at a distance of 10 cm from a concave mirror of radius of curvature 30 cm The size of the image is

[BVP 2003]

Options:

A) 9.2 cm

B) 10.5 cm

C) 5.6 cm

D) 7.5 cm

Show Answer

Answer:

Correct Answer: D

Solution:

$ R=-30cm\Rightarrow f=-15cm $

$ O=+2.5cm, $

$ u=-10cm $ By mirror formula $ \frac{1}{-15}=\frac{1}{v}+\frac{1}{(-10)}\Rightarrow v=30cm. $ .

Also $ \frac{I}{O}=-\frac{v}{u}\Rightarrow \frac{I}{(+2.5)}=-\frac{30}{(-10)} $

$ \Rightarrow I=+7.5cm. $



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