SATHEE: Optics Question 896

Optics Question 896

Question: In YDSE a light containing two wavelengths 500 nm and 700 nm are used. Find the minimum distance where maxima of two wavelengths coincide. Given $D / d = 10^{3}$ , where D is the distance between the slits and the screen and d is the distance between the slits.

Options:

A) 1.2 m

B) 3.5 mm

C) 2.8 cm

D) 8.1 mm

Show Answer

Answer:

Correct Answer: B

Solution:

[b] At the place where maxima for both the wavelengths coincide, y will be same for both the maxima, i.e.,

$\frac{n_{1} λ_{1} D}{d} = \frac{n_{2} λ_{2} D}{d} \Rightarrow \frac{n_{1}}{n_{2}} = \frac{λ_{1}}{λ_{2}} = \frac{700}{500} = \frac{7}{5}$

Minimum integral value of $n_{2}$ is 5.

Minimum distance of maxima of the two Wave lengths fr 1 om central fringe $\frac{n_{1} λ_{2} D}{d} = 5 \times 700 \times 10^{- 9} \times 10^{3} = 3.5 m m .$

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Optics Question 896

Question: In YDSE a light containing two wavelengths 500 nm and 700 nm are used. Find the minimum distance where maxima of two wavelengths coincide. Given D/d=103 , where D is the distance between the slits and the screen and d is the distance between the slits.

Options:

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Question: In YDSE a light containing two wavelengths 500 nm and 700 nm are used. Find the minimum distance where maxima of two wavelengths coincide. Given $D / d = 10^{3}$ , where D is the distance between the slits and the screen and d is the distance between the slits.