Optics Question 876

Question: The maximum number of possible interference maxima for slit separation equal to 1.8λ , where λ is the wavelength of light used, in a Young’s double slit experiment is

Options:

A) zero

B) 3

C) infinite

D) 5

Show Answer

Answer:

Correct Answer: B

Solution:

[b] As sinθ=nλd and sinθ cannot be 1

1=nλ1.8λ or n=1.8 .

Hence maximum number of possible interference maximas, 0,  ±1 i.e. 3



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