SATHEE: Optics Question 871

Optics Question 871

Question: In YDSE distance between the $S_{1}$ and $S_{2}$ is d. $P_{1}$ and $P_{2}$ are two points equidistance from O at an angular position $β$ as shown. A parallel beam of monochromatic light is incident at an angle a on the slits. Then the ratio of path difference at $P_{1}$ and $P_{2}$ is:

Options:

A) $\cot \frac{α - β}{2} \cot \frac{α + β}{2}$

B) $\tan \frac{α + β}{2} \cot \frac{α - β}{2}$

C) $\sin \frac{α + β}{2} \cos \frac{α - β}{2}$

D) $\tan \frac{α - β}{2} \cot \frac{α + β}{2}$

Show Answer

Answer:

Correct Answer: D

Solution:

[d] $\frac{Δ P_{1}}{Δ P_{2}} = \frac{\sin α - \sin β}{\sin α + s i n β} = \tan \frac{α - β}{2} \cot \frac{α + β}{2}$

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Optics Question 871

Question: In YDSE distance between the S1 and S2 is d. P1 and P2 are two points equidistance from O at an angular position β as shown. A parallel beam of monochromatic light is incident at an angle a on the slits. Then the ratio of path difference at P1 and P2 is:

Options:

Answer:

Solution:

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Question: In YDSE distance between the $S_{1}$ and $S_{2}$ is d. $P_{1}$ and $P_{2}$ are two points equidistance from O at an angular position $β$ as shown. A parallel beam of monochromatic light is incident at an angle a on the slits. Then the ratio of path difference at $P_{1}$ and $P_{2}$ is: