SATHEE: Optics Question 865

Optics Question 865

Question: In an experiment, sodium light $| μ - 1.8 | t .$ is employed and interference fringes are obtained in which 20 fringes equally spaced occupy 2.30 cm on the screen. When sodium light is replaced by blue light, the setup remaining the same otherwise, 30 fringes occupy 2.80 cm. The wavelength of blue light is

Options:

A) $4780 \overset{o}{A}$

B) $5760 \overset{o}{A}$

C) $9720 \overset{o}{A}$

D) $6390 \overset{o}{A}$

Show Answer

Answer:

Correct Answer: A

Solution:

[a] $β_{1} = \frac{2.30}{20} = \frac{D λ_{1}}{d}$ and $β_{2} = \frac{2.80}{30} = \frac{D λ_{2}}{d}$ or $\frac{β_{1}}{β_{2}} = \frac{2.30 \times 30}{20 \times 2.80} = \frac{λ_{1}}{λ_{2}}$

$∴ λ_{2} = 0.81 λ_{1} = 0.81 \times 5890 = 4780 \overset{o}{A}$

Optics Question 865

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Optics Question 865

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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