Optics Question 852

Question: White light used to illuminate the two slits in Young’s double slit experiment. The separation between the slits is d and the distance between the screen and the slit is D(»d). At a point on the screen in front of one of the slits, certain wave- lengths are missing. The missing wavelengths are

Options:

A) $ \lambda =\frac{d^{2}}{(2n+1)D} $

B) $ \lambda =\frac{(2n+1)d^{2}}{D} $

C) $ \lambda =\frac{d^{2}}{(n+1)D} $

D) $ \lambda =\frac{(n+1)D}{d^{2}} $

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Answer:

Correct Answer: A

Solution:

[a] $ n^{th} $ minimum has a distance from the centre $ =x=(2n+1)\frac{1}{2}\frac{\lambda D}{d} $ .

For a point on the screen directly in front of one of the slits, $ x=d/2 $

$ \therefore $ for minimum intensity in front of one of the slits $ \frac{d}{2}=(2n+1)\frac{\lambda }{2}\frac{D}{d} $

$ \therefore \lambda =\frac{d^{2}}{(2n+1)D} $



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