Optics Question 811

Question: A concave lens of glass, refractive index 1.5 has both surfaces of same radius of curvature R. On immersion in a medium of refractive index 1.75, it will behave as a

Options:

A) convergent lens of focal length 3.5R

B) convergent lens of focal length 3.07R

C) divergent lens of focal length 3,5R

D) divergent lens of focal length 3.07R

Show Answer

Answer:

Correct Answer: A

Solution:

[a] Use lens maker’s formula 1f=(gmμ1)(1R11R2)

Now, gmμ=gμmμ=1.51.75

1f=(1.51.751)(1R1R)=+0.25×21.75R

f+3.5R The positive sign shows that the lens behaves as convergent lens.



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