Optics Question 80

Question: A square of side $ 3cm $ is placed at a distance of $ 25cm $ from a concave mirror of focal length $ 10cm. $ The centre of the square is at the axis of the mirror and the plane is normal to the axis. The area enclosed by the image of the square is

Options:

A) $ 4cm^{2} $

B) $ 6cm^{2} $

C) $ 16cm^{2} $

D) $ 36cm^{2} $

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Answer:

Correct Answer: A

Solution:

$ m=\frac{I}{O}=\frac{f}{u-f}=\frac{10}{25-10}=\frac{10}{15}=\frac{2}{3} $

$ m^{2}=\frac{A _{i}}{A _{o}}\Rightarrow A _{i}=m^{2}\times A _{o} $

$ ={{( \frac{2}{3} )}^{2}}\times {{(3)}^{2}}=4cm^{2} $



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