Optics Question 792

Question: A ray parallel to principal axis is incident at 30∘ from normal on concave mirror having radius of curvature R. The point on principal axis where rays are focused is Q such that PQ is

Options:

A) R2

B) R3

C) 2R−R2

D) R(1−13)

Show Answer

Answer:

Correct Answer: D

Solution:

[d] From similar triangles, QCsin⁡30∘=Rsin⁡120∘

or QC=R×sin⁡30∘sin⁡120∘=R3

Thus PQ=PC−QC=R−R3=R(1−13)

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