Optics Question 763
Question: A ray of light is incident on a transparent glass slab of refractive index 1.62. The reflected and the refracted rays are mutually perpendicular. The angle of incidence is
[MP PET 2002]
Options:
A) 58.3o
B) 50o
C) 35o
D) 30o
Show Answer
Answer:
Correct Answer: A
Solution:
$ \mu =\tan i $
Therefore i = $ {{\tan }^{-1}}\mu ={{\tan }^{-1}}1.62=58.3{}^\circ $