Optics Question 754

Question: A ray of light is incident on the surface of separation of a medium at an angle $ 45{}^\circ $ and is refracted in the medium at an angle $ 30{}^\circ $ . What will be the velocity of light in the medium

[AFMC 1998; MH CET (Med.) 1999]

Options:

A) $ 1.96\times 10^{8} $ m/s

B) $ 2.12\times 10^{8} $ $ m/s $

C) $ 3.18\times 10^{8} $ $ m/s $

D) $ 3.33\times 18^{8} $ $ m/s $

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Answer:

Correct Answer: B

Solution:

$ \mu =\frac{c}{v}=\frac{\sin i}{\sin r}=\frac{\sin 45^{o}}{\sin 30^{o}} $

$ \Rightarrow $ $ v=\frac{3\times 10^{8}}{\sqrt{2}}=2.12\times 10^{8} $ $ m/s $



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