Optics Question 723

Question: If $ _{i}{\mu _{j}} $ represents refractive index when a light ray goes from medium i to medium j, then the product $ _{2}{\mu _{1}}\times _{3}{\mu _{2}}\times _{4}{\mu _{3}} $ is equal to

[CBSE PMT 1990]

Options:

A) $ _{3}{\mu _{1}} $

B) $ _{3}{\mu _{2}} $

C) $ \frac{1}{ _{1}{\mu _{4}}} $

D) $ _{4}{\mu _{2}} $

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Answer:

Correct Answer: C

Solution:

$ _{2}{\mu _{1}}{\times _{3}}{\mu _{2}}{\times _{4}}{\mu _{3}}=\frac{{\mu _{1}}}{{\mu _{2}}}\times \frac{{\mu _{2}}}{{\mu _{3}}}\times \frac{{\mu _{3}}}{{\mu _{4}}}=\frac{{\mu _{1}}}{{\mu _{4}}}{= _{4}}{\mu _{1}}=\frac{1}{ _{1}{\mu _{4}}} $



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