Optics Question 667

Question: A point object O is placed in front of a glass rod having spherical end of radius of curvature 30 cm. The image would be formed at

[Orissa JEE 2002]

Options:

A) 30 cm left

B) Infinity

C) 1 cm to the right

D) 18 cm to the left

Show Answer

Answer:

Correct Answer: A

Solution:

By using formula $ \frac{{\mu _{2}}}{v}-\frac{{\mu _{1}}}{u}=\frac{{\mu _{2}}-{\mu _{1}}}{R} $

$ \Rightarrow $ $ \frac{1.5}{v}-\frac{1}{(-15)}=\frac{(1.5-1)}{+30}\Rightarrow v=-30cm $ .

Negative sign shows that, image is obtained on the same side of object i.e. towards left.



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