Optics Question 665

Question: An object is placed 12 cm to the left of a converging lens of focal length 8 cm. Another converging lens of 6 cm focal length is placed at a distance of 30 cm to the right of the first lens. The second lens will produce

[KCET 2002]

Options:

A) No image

B) A virtual enlarged image

C) A real enlarged image

D) A real smaller image

Show Answer

Answer:

Correct Answer: C

Solution:

For lens (1) $ \frac{1}{f}=\frac{1}{v}-\frac{1}{u}\Rightarrow \frac{1}{(+8)}=\frac{1}{v}-\frac{1}{(-12)} $

$ \Rightarrow v=24 $ $ cm $ i.e.

Image $ A’B’ $ is obtained 6 cm before the lens 2 or at the focus of lens 2.

Hence final image formed by lens 2 will be real enlarged and it is obtained at $ \infty $ .



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