Optics Question 603

Question: A biconvex lens forms a real image of an object placed perpendicular to its principal axis. Suppose the radii of curvature of the lens tend to infinity. Then the image would

[MP PET 1994]

Options:

A) Disappear

B) Remain as real image still

C) Be virtual and of the same size as the object

D) Suffer from aberrations

Show Answer

Answer:

Correct Answer: C

Solution:

$ \frac{1}{f}=(\mu -1)( \frac{1}{R _{1}}-\frac{1}{R _{2}} ) $ For biconvex lens $ R _{2}=-R _{1} $

$ \therefore $ $ \frac{1}{f}=(\mu -1)( \frac{2}{R} ) $ Given $ R=\infty $

$ \therefore $ $ f=\infty $ , so no focus at real distance.



NCERT Chapter Video Solution

Dual Pane