SATHEE: Optics Question 566

Optics Question 566

Question: Unpolarized light of intensity 32Wm?2 passes through three polarizers such that transmission axes of the first and second polarizer makes and angle 30° with each other and the transmission axis of the last polarizer is crossed with that of the first. The intensity of final emerging light will be

Options:

A) 32 Wm?2

B) 3 Wm?2

C) 8 Wm?2

D) 4 Wm?2

Show Answer

Answer:

Correct Answer: B

Solution:

Angle between P1 and P2 = 30° (given) Angle between P2 and P3 = q = 90° - 30° = 60°

The intensity of light transmitted by P1 is $I_{1} = \frac{I_{0}}{2} = \frac{32}{2} = 16 \frac{W}{m^{2}}$ .

According to Malus law the intensity of light transmitted by P2 is $I_{2} = I_{1} \cos^{2} 30^{\circ} = 16 {(\frac{\sqrt{3}}{2})}^{2} = 12 \frac{W}{m^{2}}$ .

Similarly intensity of light transmitted by P3 is $I_{3} = I_{2} \cos^{2} θ = 12 \cos^{2} 60^{\circ} = 12 {(\frac{1}{2})}^{2} = 3 \frac{W}{m^{2}}$

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Optics Question 566

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