SATHEE: Optics Question 546

Optics Question 546

Question: The angle of polarization for any medium is 60o, what will be critical angle for this

[UPSEAT 1999]

Options:

A) $\sin^{- 1} \sqrt{3}$

B) $\tan^{- 1} \sqrt{3}$

C) $\cos^{- 1} \sqrt{3}$

D) $\sin^{- 1} \frac{1}{\sqrt{3}}$

Show Answer

Answer:

Correct Answer: D

Solution:

By using $μ = \tan θ_{p} \Rightarrow μ = \tan 60 = \sqrt{3}$ , also $C = \sin^{- 1} (\frac{1}{μ}) \Rightarrow C = \sin^{- 1} (\frac{1}{\sqrt{3}})$

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