Optics Question 491

Question: The distance between a point source of light and a screen which is 60 cm is increased to 180 cm. The intensity on the screen as compared with the original intensity will be

[CPMT 1888]

Options:

A) (1 / 9) times

B) (1 / 3) times

C) 3 times

D) 9 times

Show Answer

Answer:

Correct Answer: A

Solution:

I1r2

I2I1=r12r22

=6021802=19



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