SATHEE: Optics Question 467

Optics Question 467

Question: In Young’s double-slit experiment, the angular width of a fringe formed on a distant screen is $1^{\circ} .$ The wavelength of light used is $6000 \overset{o}{A}$ . What is the spacing between the slits?

Options:

A) 344 mm

B) 0.1344 mm

C) 0.0344 mm

D) 0.034 mm

Show Answer

Answer:

Correct Answer: C

Solution:

[c] In Young’s double slit fringe with $\sin θ = θ = y / D$

So, $Δ y / D$ and hence angular fringe width $θ_{0} = Δ θ (w i t h Δ y = β)$ Will be $θ_{0} = \frac{β}{D} = \frac{D λ}{d} \times \frac{1}{D} = \frac{λ}{d}$

$\Rightarrow θ_{0} = 1^{0} = (\frac{π}{180})$ rad, and $λ = 6 \times 10^{- 7} m$ Or $d = \frac{λ}{θ_{0}} = \frac{180}{π} \times (6 \times 10^{- 7}) = 3.44 \times 10^{- 5} m$ Or $d = 0.0344 m m$

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Optics Question 467

Question: In Young’s double-slit experiment, the angular width of a fringe formed on a distant screen is 1∘. The wavelength of light used is 6000Ao . What is the spacing between the slits?

Options:

Answer:

Solution:

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Question: In Young’s double-slit experiment, the angular width of a fringe formed on a distant screen is $1^{\circ} .$ The wavelength of light used is $6000 \overset{o}{A}$ . What is the spacing between the slits?