Optics Question 459

Question: In the Young’s double slit experiment, if the phase difference between the two waves interfering at a point is $ \phi $ , the intensity at that point can be expressed by the expression

Options:

A) $ I=\sqrt{A^{2}+B^{2}{{\cos }^{2}}\varphi } $

B) $ I=\frac{A}{B}\cos \varphi $

C) $ I=A+B\cos \frac{\varphi }{2} $

D) $ I=A+B\cos $

Show Answer

Answer:

Correct Answer: D

Solution:

[d] $ I=a _{1}^{2}+a _{2}^{2}+2a _{1}a _{2}\cos \varphi $

Put $ a _{1}^{2}+a _{2}^{2}=A $ and $ a _{1}a _{2}=B $

$ \therefore I=A+B\cos \varphi $



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