Optics Question 445

Question: Critical angle of glass is $ {\theta _{1}} $ and that of water is $ {\theta _{2}} $ . The critical angle for water and glass surface would be $ ({\mu _{g}}=3/2,{\mu _{w}}=4/3) $

Options:

A) Less than $ {\theta _{2}} $

B) Between $ {\theta _{1}} $ and $ {\theta _{2}} $

C) Greater than $ {\theta _{2}} $

D) Less than $ {\theta _{1}} $

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Answer:

Correct Answer: C

Solution:

[c] $ \sin {\theta _{1}}=\frac{1}{{\mu _{g}}} $

and $ \sin {\theta _{2}}=\frac{1}{{\mu _{w}}} $

Since $ {\mu _{g}}>{\mu _{w,}}{\theta _{1}}<{\theta _{2}} $

Critical angle $ \theta $ between glass and water will be given by $ \sin \theta =\frac{{\mu _{w}}}{{\mu _{g}}} $ Or $ \theta >{\theta _{2}} $



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