Optics Question 438

Question: Magnification of a compound microscope is 30. Focal length of eye-piece is 5 cm and the image is formed at a distance of distinct vision of 25 cm. The magnification of the objective lens is

[DPMT 2005]

Options:

A) 6

B) 5

C) 7.5

D) 10

Show Answer

Answer:

Correct Answer: B

Solution:

m=vouo(1+Dfe)=mo(1+Dfe)

Therefore 30=mo(1+255)=m0×6

Therefore mo=5 .



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