SATHEE: Optics Question 436

Optics Question 436

Question: The diameter of objective of a telescope is 1m. Its resolving limit for the light of wave length 4538 Å, will be

[Pb. PET 2003]

Options:

A) $5.54 \times 10^{- 7} r a d$

B) $2.54 \times 10^{- 4} r a d$

C) $6.54 \times 10^{- 7} r a d$

D) None of these

Show Answer

Answer:

Correct Answer: A

Solution:

Resolving limit $d θ = \frac{1.22 λ}{a} = \frac{1.22 \times 4538 \times 10^{- 10}}{1}$

$= 5.54 \times 10^{- 7} r a d$ .

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Optics Question 436

Question: The diameter of objective of a telescope is 1m. Its resolving limit for the light of wave length 4538 Å, will be

Options:

Answer:

Solution:

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