SATHEE: Optics Question 377

Optics Question 377

Question: The diameter of the objective of the telescope is 0.1 metre and wavelength of light is 6000 Å. Its resolving power would be approximately

[MP PET 1997]

Options:

A) $7.32 \times 10^{- 6} r a d$

B) $1.36 \times 10^{6} r a d$

C) $7.32 \times 10^{- 5} r a d$

D) $1.36 \times 10^{5} r a d$

Show Answer

Answer:

Correct Answer: D

Solution:

Resolving power $= \frac{d}{1.22 λ} = \frac{0.1}{1.22 \times 6000 \times 10^{- 10}}$

$≅ 1.36 \times 10^{5} r a d i a n$

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Optics Question 377

Question: The diameter of the objective of the telescope is 0.1 metre and wavelength of light is 6000 Å. Its resolving power would be approximately

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu