Optics Question 377

Question: The diameter of the objective of the telescope is 0.1 metre and wavelength of light is 6000 Å. Its resolving power would be approximately

[MP PET 1997]

Options:

A) $ 7.32\times {{10}^{-6}}rad $

B) $ 1.36\times 10^{6}rad $

C) $ 7.32\times {{10}^{-5}}rad $

D) $ 1.36\times 10^{5}rad $

Show Answer

Answer:

Correct Answer: D

Solution:

Resolving power $ =\frac{d}{1.22\ \lambda }=\frac{0.1}{1.22\times 6000\times {{10}^{-10}}} $

$ \cong 1.36\times 10^{5}radian $



NCERT Chapter Video Solution

Dual Pane