SATHEE: Optics Question 326

Optics Question 326

Question: The intensity of gamma radiation from a given source is I. On passing through 36 mm of lead, it is reduced to $\frac{I}{8}$ . The thickness of lead which will reduce the intensity to $\frac{I}{2}$ will be

[AIEEE 2005]

Options:

A) 18 mm

B) 12 mm

C) 6 mm

D) 9 mm

Show Answer

Answer:

Correct Answer: B

Solution:

$I^{'} = I e^{- μ x}$

Therefore $x = \frac{1}{μ} \log_{e} \frac{I}{I^{'}}$ (where I = original intensity, I’ = changed intensity) $36 = \frac{1}{μ} \log_{e} \frac{I}{I / 8}$ = $\frac{3}{μ} \log_{e} 2$ ….(i) $x = \frac{1}{μ} \log_{e} \frac{I}{I / 2}$

$= \frac{1}{μ} \log_{e} 2$ …..(ii) From equation (i) and (ii), $x = 12 m m$ .

Optics Question 326

Question: The intensity of gamma radiation from a given source is I. On passing through 36 mm of lead, it is reduced to $\frac{I}{8}$ . The thickness of lead which will reduce the intensity to $\frac{I}{2}$ will be

Options:

Answer:

Solution:

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Optics Question 326

Question: The intensity of gamma radiation from a given source is I. On passing through 36 mm of lead, it is reduced to I8 . The thickness of lead which will reduce the intensity to I2 will be

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: The intensity of gamma radiation from a given source is I. On passing through 36 mm of lead, it is reduced to $\frac{I}{8}$ . The thickness of lead which will reduce the intensity to $\frac{I}{2}$ will be