Optics Question 301
Question: TV waves have a wavelength range of 1-10 meter. Their frequency range in MHz is
[KCET 1998]
Options:
A) 30-300
B) 3-30
C) 300-3000
D) 3-3000
Show Answer
Answer:
Correct Answer: A
Solution:
$ v=\frac{C}{\lambda }\Rightarrow v _{1}=\frac{3\times 10^{8}}{1} $ = $ 3\times 10^{8}Hz=300\ MHz $
and $ v _{2}=\frac{3\times 10^{8}}{10} $ = $ 3\times 10^{7}Hz=30MHz $