Optics Question 255

Question: The wavelength of light observed on the earth, from a moving star is found to decrease by 0.05%. Relative to the earth the star is

[MP PMT/PET 1998]

Options:

A) Moving away with a velocity of $ 1.5\times 10^{5}m/s $

B) Coming closer with a velocity of $ 1.5\times 10^{5}m/s $

C) Moving away with a velocity of $ 1.5\times 10^{4}m/s $

D) Coming closer with a velocity of $ 1.5\times 10^{4}m/s $

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Answer:

Correct Answer: B

Solution:

$ \frac{\Delta \lambda }{\lambda }=\frac{v}{c}\Rightarrow \frac{0.05}{100}=\frac{v}{3\times 10^{8}} $

Therefore v = 1.5 x 105 m/s (Since wavelength is decreasing, so star coming closer)



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