Optics Question 236

Question: A star producing light of wavelength $ 6000{AA} $ moves away from the earth with a speed of 5 km/sec. Due to Doppler effect the shift in wavelength will be $ (c=3\times 10^{8}m/\sec ) $

[MP PMT 1990]

Options:

A) $ 0.1{AA} $

B) $ 0.05{AA} $

C) $ 0.2{AA} $

D) $ 1{AA} $

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Answer:

Correct Answer: A

Solution:

Doppler’s shift is given by $ \Delta \lambda =\frac{v\lambda }{c}=\frac{5000\times 6000}{3\times 10^{8}}=0.1{AA} $



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