Optics Question 232

Question: Light of wavelength λ=5000AA falls normally on a narrow slit. A screen placed at a distance of 1 m from the slit and perpendicular to the direction of light. The first minima of the diffraction pattern is situated at 5 mm from the centre of central maximum. The width of the slit is

Options:

A) 0.1 mm

B) 1.0 mm

C) 0.5 mm

D) 0.2 mm

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Answer:

Correct Answer: A

Solution:

Position of nth minima xn=nλDd

5×103=1×5000×1010×1d

d=104m=0.1mm .



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