SATHEE: Optics Question 231

Optics Question 231

Question: In the far field diffraction pattern of a single slit under polychromatic illumination, the first minimum with the wavelength $λ_{1}$ is found to be coincident with the third maximum at $λ_{2}$ . So

Options:

A) $3 λ_{1} = 0.3 λ_{2}$

B) $3 λ_{1} = λ_{2}$

C) $λ_{1} = 3.5 λ_{2}$

D) $0.3 λ_{1} = 3 λ_{2}$

Show Answer

Answer:

Correct Answer: C

Solution:

Position of first minima = position of third maxima i.e., $\frac{1 \times λ_{1} D}{d} = \frac{(2 \times 3 + 1)}{2} \frac{λ_{2} D}{d} \Rightarrow λ_{1} = 3.5 λ_{2}$

Optics Question 231

Question: In the far field diffraction pattern of a single slit under polychromatic illumination, the first minimum with the wavelength $λ_{1}$ is found to be coincident with the third maximum at $λ_{2}$ . So

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Optics Question 231

Question: In the far field diffraction pattern of a single slit under polychromatic illumination, the first minimum with the wavelength λ1 is found to be coincident with the third maximum at λ2 . So

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: In the far field diffraction pattern of a single slit under polychromatic illumination, the first minimum with the wavelength $λ_{1}$ is found to be coincident with the third maximum at $λ_{2}$ . So