Optics Question 206

Question: A plane wavefront $ (\lambda =6\times {{10}^{-7}}m) $ falls on a slit $ 0.4mm $ wide. A convex lens of focal length $ 0.8m $ placed behind the slit focusses the light on a screen. What is the linear diameter of second maximum

[RPMT 2001]

Options:

A) $ 6mm $

B) $ 12mm $

C) $ 3mm $

D) $ 9mm $

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Answer:

Correct Answer: A

Solution:

For secondary maxima $ d\sin \theta =\frac{5\lambda }{2} $

$ \Rightarrow d\theta =d.\frac{x}{D(\approx f)}=\frac{5\lambda }{2} $

$ \Rightarrow 2x=\frac{5\lambda f}{d}=\frac{5\times 0.8\times {{10}^{-7}}}{4\times {{10}^{-4}}}=6\times {{10}^{-3}}m=6mm $



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