Optics Question 200

Question: What will be the angle of diffracting for the first minimum due to Fraunhoffer diffraction with sources of light of wave length 550 nm and slit of width 0.55 mm

[Pb. PMT 2001]

Options:

A) 0.001 rad

B) 0.01 rad

C) 1 rad

D) 0.1 rad

Show Answer

Answer:

Correct Answer: A

Solution:

Using $ d\sin \theta =n\lambda , $ for n =1 $ \sin \theta =\frac{\lambda }{d}=\frac{550\times {{10}^{-9}}}{0.55\times {{10}^{-3}}}={{10}^{-3}}=0.001\ rad $



NCERT Chapter Video Solution

Dual Pane