Optics Question 192

Question: In Young’s double slit experiment intensity at a point is (1/4) of the maximum intensity. Angular position of this point is

[IIT-JEE (Screening) 2005]

Options:

A) sin-1(l/d)

B) sin-1(l/2d)

C) sin-1(l/3d)

D) sin-1(l/4d)

Show Answer

Answer:

Correct Answer: C

Solution:

$ I=4I _{0} $ cos2(f/2)

Therefore f = 2p/3

Therefore Dx x (2p/l) = 2p/3= l/3 sin q = Dx/d

Therefore sin q = l/3d



NCERT Chapter Video Solution

Dual Pane