Optics Question 180
Question: A point source of electromagnetic radiation has an average power output of 800 W. The maximum value of electric field at a distance 4.0 m from the source is
Options:
A) 64.7 V/m
B) 57.8 V/m
C) 56.72 V/m
D) 54.77 V/m
Show Answer
Answer:
Correct Answer: D
Solution:
Intensity of EM wave is given by
Therefore
