Optics Question 171

Question: Light is incident normally on a diffraction grating through which the first order diffraction is seen at 32o. The second order diffraction will be seen at

Options:

A) 48o

B) 64o

C) 80o

D) There is no second order diffraction in this case

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Answer:

Correct Answer: D

Solution:

For a grating $ (e+d)\sin {\theta _{n}}=n\lambda $

where $ (e+d)= $ grating element $ \sin {\theta _{n}}=\frac{n\lambda }{(e+d)} $ For $ n=1, $

$ \sin {\theta _{1}}=\frac{\lambda }{(e+d)}=\sin 32{}^\circ $

This is more than 0.5. Now $ \sin {\theta _{2}} $ will be more than $ 2\times 0.5, $ which is not possible.



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