Optics Question 157

Question: A flake of glass (refractive index 1.5) is placed over one of the openings of a double slit apparatus. The interference pattern displaces itself through seven successive maxima towards the side where the flake is placed. if wavelength of the diffracted light is λ=600nm , then the thickness of the flake is

Options:

A) 2100 nm

B) 4200 nm

C) 8400 nm

D) None of these

Show Answer

Answer:

Correct Answer: C

Solution:

Shift =βλ(μ1)t

7β=βλ(μ1)tt=7λ(μ1)

=7×600(1.51)=8400nm.



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