Optics Question 156
Question: In a Young’s double slit experiment, the slits are 2 mm apart and are illuminated with a mixture of two wavelength and . The minimum distance from the common central bright fringe on a screen 2m from the slits where a bright fringe from one interference pattern coincides with a bright fringe from the other is
Options:
A) 1.5 mm
B) 3 mm
C) 4.5 mm
D) 6 mm
Show Answer
Answer:
Correct Answer: C
Solution:
From the given data, note that the fringe width (b1) for
This means that at though the central maxima of the two coincide, but first maximum for
A stage may come when this mismatch equals b2, then again maxima of
let this correspond to nth order fringe for l1. Then it will correspond to
Therefore
Minimum distance from Central maxima