SATHEE: Optics Question 1152

Optics Question 1152

Question: If prism angle $α = 1^{\circ}, μ = 1.54,$ distance between screen and prism $(b) = 0.7 m,$ distance between prism and source $a = 0.3 m, λ = 180 π n m$ then in Fresnal biprism find the value of $β$ (fringe width)

[RPMT 2002]

Options:

A) $10^{- 4} m$

B) $10^{- 3} m m$

C) $10^{- 4} \times π m$

D) $π \times 10^{- 3} m$

Show Answer

Answer:

Correct Answer: A

Solution:

By using $β = \frac{(a + b) λ}{2 a (μ - 1) α} = \frac{(0.3 + 0.7) \times 180 π \times 10^{- 9}}{2 \times 0.3 (1.54 - 1) \times (1 \times \frac{π}{180})}$ = $10^{- 4} m$

Optics Question 1152

Question: If prism angle $α = 1^{\circ}, μ = 1.54,$ distance between screen and prism $(b) = 0.7 m,$ distance between prism and source $a = 0.3 m, λ = 180 π n m$ then in Fresnal biprism find the value of $β$ (fringe width)

Options:

Answer:

Solution:

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Optics Question 1152

Question: If prism angle α=1∘, μ=1.54, distance between screen and prism (b)=0.7m, distance between prism and source a=0.3m, λ=180π nm then in Fresnal biprism find the value of β (fringe width)

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: If prism angle $α = 1^{\circ}, μ = 1.54,$ distance between screen and prism $(b) = 0.7 m,$ distance between prism and source $a = 0.3 m, λ = 180 π n m$ then in Fresnal biprism find the value of $β$ (fringe width)