Optics Question 1143

Question: Two coherent sources of intensity ratio 1 : 4 produce an interference pattern. The fringe visibility will be

[J & K CET 2004]

Options:

A) 1

B) 0.8

C) 0.4

D) 0.6

Show Answer

Answer:

Correct Answer: B

Solution:

$ \frac{I _{1}}{I _{2}}=\frac{1}{4}\Rightarrow I _{1}=k $ and $ I _{2}=4k $

$ \therefore $ Fringe visibility $ V=\frac{2\sqrt{I _{1}I _{2}}}{(I _{1}+I _{2})}=\frac{2\sqrt{k\times 4k}}{(k+4k)}=0.8 $



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