Optics Question 1111

Question: In Young’s experiment, the distance between slits is 0.28 mm and distance between slits and screen is 1.4 m. Distance between central bright fringe and third bright fringe is 0.9 cm. What is the wavelength of used light

[KCET 1999]

Options:

A) 5000AA

B) 6000AA

C) 7000AA

D) 9000AA

Show Answer

Answer:

Correct Answer: B

Solution:

Position of 3rd bright fringe x3=3Dλd

λ=x3d3D=(0.9×102)×(0.28×103)3×1.4=6000AA



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