Optics Question 1106

Question: In Young’s double slit experiment, the distance between sources is 1 mm and distance between the screen and source is 1 m. If the fringe width on the screen is 0.06 cm, then l =

[CPMT 1996]

Options:

A) $ 6000{AA} $

B) $ 4000{AA} $

C) $ 1200{AA} $

D) $ 2400{AA} $

Show Answer

Answer:

Correct Answer: A

Solution:

$ \beta =\frac{\lambda D}{d}\Rightarrow (0.06\times {{10}^{-2}})=\frac{\lambda \times 1}{1\times {{10}^{-3}}} $

$ \Rightarrow \lambda =6000{AA} $



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