Optics Question 1106

Question: In Young’s double slit experiment, the distance between sources is 1 mm and distance between the screen and source is 1 m. If the fringe width on the screen is 0.06 cm, then l =

[CPMT 1996]

Options:

A) 6000AA

B) 4000AA

C) 1200AA

D) 2400AA

Show Answer

Answer:

Correct Answer: A

Solution:

β=λDd(0.06×102)=λ×11×103

λ=6000AA



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