Optics Question 1099

Question: In Young’s double slit experiment, the slits are 0.5 mm apart and interference pattern is observed on a screen placed at a distance of 1.0 m from the plane containing the slits. If wavelength of the incident light is 6000 Å, then the separation between the third bright fringe and the central maxima is

[AMU 1995]

Options:

A) 4.0 mm

B) 3.5 mm

C) 3.0 mm

D) 2.5 mm

Show Answer

Answer:

Correct Answer: B

Solution:

Separation nth bright fringe and central maxima is xn=nλDd .

So, x3=3×6000×1010×10.5×103=3.5mm.



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