Optics Question 1091

Question: In Young’s double slit experiment, the fringe width is 1×10−4m if the distance between the slit and screen is doubled and the distance between the two slit is reduced to half and wavelength is changed from 6.4×107m to 4.0×10−7m , the value of new fringe width will be

Options:

A) 0.15×10−4m

B) 2.0×10−4m

C) 1.25×10−4m

D) 2.5×10−4m

Show Answer

Answer:

Correct Answer: D

Solution:

β=λDd

⇒β2β1=λ2D2d1λ1D1d2

⇒β2=2.5×10−4m .

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