Optics Question 1075

Question: In the Young’s double slit experiment, the ratio of intensities of bright and dark fringes is 9. This means that

[IIT 1982]

Options:

A) The intensities of individual sources are 5 and 4 units respectively

B) The intensities of individual sources are 4 and 1 units respectively

C) The ratio of their amplitudes is 3

D) The ratio of their amplitudes is 2

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Answer:

Correct Answer: B

Solution:

$ \frac{{I _{\max }}}{{I _{\min }}}=9\Rightarrow {{( \frac{a _{1}+a _{2}}{a _{1}-a _{2}} )}^{2}}=9\Rightarrow \frac{a _{1}+a _{2}}{a _{1}-a _{2}}=3 $

$ \Rightarrow \frac{a _{1}}{a _{2}}=\frac{3+1}{3-1}\Rightarrow \frac{a _{1}}{a _{2}}=2. $

Therefore $ I _{1}:I _{2}=4:1 $



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