Optics Question 1067

Question: In Young’s double slit experiment, if the slit widths are in the ratio 1 : 9, then the ratio of the intensity at minima to that at maxima will be

[MP PET 1987]

Options:

A) 1

B) 1/9

C) 1/4

D) 1/3

Show Answer

Answer:

Correct Answer: C

Solution:

Slit width ratio = 1 : 9 Since slit width ratio is the ratio of intensity and intensity $ \propto $ (amplitude)2

$ \therefore I _{1}:I _{2}=1:9 $

$ \Rightarrow a _{1}^{2}:a _{2}^{2}=1:9\Rightarrow a _{1}:a _{2}=1:3 $

$ {I _{\max }}={{(a _{1}+a _{2})}^{2}},\ \ {I _{\min }}={{(a _{1}-a _{2})}^{2}}\Rightarrow \frac{{I _{\min }}}{{I _{\max }}}=\frac{1}{4} $



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