Optics Question 1063

Question: Two waves of intensity I undergo Interference. The maximum intensity obtained is

[BHU 2005]

Options:

A) I / 2

B) I

C) 2I

D) 4I

Show Answer

Answer:

Correct Answer: D

Solution:

For maximum intensity φ=0 \ I=I1+I2+2I1I2cosφ

=I+I+2IIcos0=4I



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