Optics Question 1063
Question: Two waves of intensity I undergo Interference. The maximum intensity obtained is
[BHU 2005]
Options:
A) I / 2
B) I
C) 2I
D) 4I
Show Answer
Answer:
Correct Answer: D
Solution:
For maximum intensity $ \varphi =0{}^\circ $ \ $ I=I _{1}+I _{2}+2\sqrt{I _{1}I _{2}}\cos \varphi $
$ =I+I+2\sqrt{II}\cos 0{}^\circ =4I $
