Optics Question 1047
Question: Two waves have their amplitudes in the ratio 1 : 9. The maximum and minimum intensities when they interfere are in the ratio
[KCET 2002]
Options:
A) $ \frac{25}{16} $
B) $ \frac{16}{26} $
C) $ \frac{1}{9} $
D) $ \frac{9}{1} $
Show Answer
Answer:
Correct Answer: A
Solution:
$ \frac{{I _{\max }}}{{I _{\min }}}={{( \frac{\frac{a _{1}}{a _{2}}+1}{\frac{a _{1}}{a _{2}}-1} )}^{2}}={{( \frac{\frac{1}{9}+1}{\frac{1}{9}-1} )}^{2}}={{( \frac{5}{4} )}^{2}}=\frac{25}{16}. $
