Optics Question 1047

Question: Two waves have their amplitudes in the ratio 1 : 9. The maximum and minimum intensities when they interfere are in the ratio

[KCET 2002]

Options:

A) $ \frac{25}{16} $

B) $ \frac{16}{26} $

C) $ \frac{1}{9} $

D) $ \frac{9}{1} $

Show Answer

Answer:

Correct Answer: A

Solution:

$ \frac{{I _{\max }}}{{I _{\min }}}={{( \frac{\frac{a _{1}}{a _{2}}+1}{\frac{a _{1}}{a _{2}}-1} )}^{2}}={{( \frac{\frac{1}{9}+1}{\frac{1}{9}-1} )}^{2}}={{( \frac{5}{4} )}^{2}}=\frac{25}{16}. $



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