Optics Question 1043

Question: Light waves producing interference have their amplitudes in the ratio 3 : 2. The intensity ratio of maximum and minimum of interference fringes is

[EAMCET 2001]

Options:

A) 36 : 1

B) 9 : 4

C) 25 : 1

D) 6 : 4

Show Answer

Answer:

Correct Answer: C

Solution:

$ \frac{{I _{\max }}}{{I _{\min }}}={{( \frac{\frac{a _{1}}{a _{2}}+1}{\frac{a _{1}}{a _{2}}-1} )}^{2}}=\frac{25}{1} $



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