Optics Question 1043
Question: Light waves producing interference have their amplitudes in the ratio 3 : 2. The intensity ratio of maximum and minimum of interference fringes is
[EAMCET 2001]
Options:
A) 36 : 1
B) 9 : 4
C) 25 : 1
D) 6 : 4
Show Answer
Answer:
Correct Answer: C
Solution:
$ \frac{{I _{\max }}}{{I _{\min }}}={{( \frac{\frac{a _{1}}{a _{2}}+1}{\frac{a _{1}}{a _{2}}-1} )}^{2}}=\frac{25}{1} $
